JEE MainPhysicsRay Optics
A short linear object of length 2 mm lies along the principal axis of a convex mirror of focal length 20 cm . If the object is placed at a distance of 30 cm from the pole of the mirror, the length of the image formed is :
Options
- A0.8 mm
- B0.32 mm
- C8.0 mm
- D12.5 mm
Correct answer
B. 0.32 mm
Step-by-step solution
Given focal length of the convex mirror f = +20 cm . Object distance u = -30 cm . Length of the object L_o = 2 mm . First, calculate the lateral magnification m for the center of the object: m = f f - u m = 20 20 - (-30) = 20 50 = 2 5 For a short linear object placed along the principal axis, the longitudinal magnification m_L is given by the square of the lateral magnification: m_L = m^2 = ( 2 5 )^2 = 4 25 The length of the image L_i is: L_i = m_L L_o L_i = 4 25 2 mm = 8 25 mm = 0.32 mm Answer: 0.32 mm