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JEE MainPhysicsElectromagnetic Waves

An electromagnetic wave propagating in vacuum has an electric field amplitude E₀ and a magnetic field amplitude B₀ . If the angular frequency of the wave is , the propagation constant (wave number) k of the wave is given by:

Options

  1. Ak = E₀ B₀
  2. Bk = B₀ E₀
  3. Ck = E₀ B₀
  4. Dk = B₀ E₀

Correct answer

B. k = B₀ E₀

Step-by-step solution

The speed of an electromagnetic wave in vacuum is given by the ratio of the electric field amplitude to the magnetic field amplitude: c = E₀ B₀ The speed of the wave is also related to its angular frequency and wave number k by the relation: c = k Equating the two expressions for c , we get: E₀ B₀ = k Rearranging this equation to solve for k , we obtain: k = B₀ E₀ Answer: k = B₀ E₀

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