JEE MainPhysicsMagnetic Effects of Current
A steady current I flows in a wire configured in 3D space. The wire comes from z = + down to z = 0 along the line x = R, y = 0 . Then it follows a quarter-circular arc in the xy -plane from (R,0,0) to (0,R,0) centered at the origin. Finally, it goes from z = 0 to z = + along the line x = 0, y = R . The magnitude of the net magnetic field at the origin (0,0,0) is:
Options
- A₀ I 8 R (4 + )
- B₀ I 8 R (2 2 )
- C₀ I 8 R 16 + ^2
- D₀ I 8 R 8 + ^2
Correct answer
D. ₀ I 8 R 8 + ^2
Step-by-step solution
The wire consists of three segments, and we calculate the magnetic field vector of each at the origin (0,0,0) . Segment 1: The semi-infinite straight wire from z = + to z = 0 at x = R, y = 0 . The perpendicular distance to the origin is R . The magnitude is B₁ = ₀ I 4 R . The current flows in the - k direction and the position vector from the wire to the origin is in the - i direction. By the Biot-Savart law ( d l r ), the field is in the (- k ) (- i ) = + j direction. So, B ₁ = ₀ I 4 R j . Segment 2: The quarter-c