JEE MainPhysicsElectrostatics
An electric dipole of dipole moment 5 10⁻⁶ C m and moment of inertia 2 10⁻⁴ kg m ^2 is held at an angle of 90^ with respect to a uniform electric field of 2 10^3 N C ⁻¹ . If the dipole is released from rest, its maximum angular velocity as it rotates will be _____ rad s ⁻¹ .
Correct answer
10
Step-by-step solution
The maximum angular velocity is attained when the dipole passes through its stable equilibrium position, i.e., when the angle between the dipole moment and the electric field is 0^ . By the principle of conservation of mechanical energy: K_i + U_i = K_f + U_f Initially, the dipole is at rest ( K_i = 0 ) at = 90^ . Its initial potential energy is: U_i = -pE 90^ = 0 Finally, at = 0^ , the kinetic energy is K_f = 1 2 I ^2 and the potential energy is: U_f = -pE 0^ = -pE Substituting these into the energy conservation e