JEE MainPhysicsMathematics in Physics
The momentum ( p ) and mass ( m ) of a moving body are measured in a laboratory as p = (50 1) kg m/s m = (10 0.5) kg The percentage error in the calculated kinetic energy of the body is:
Options
- A9 %
- B7 %
- C6 %
- D1 %
Correct answer
A. 9 %
Step-by-step solution
The kinetic energy K of a body is related to its momentum p and mass m by the formula: K = p^2 2m The maximum fractional error in kinetic energy is given by: K K = 2 p p + m m Multiplying by 100 to get the percentage error: K K 100 = 2 ( p p 100 ) + ( m m 100 ) Given values: p p 100 = 1 50 100 = 2 % m m 100 = 0.5 10 100 = 5 % Substituting these values into the error formula: Percentage error in K = 2(2 %) + 5 % = 4 % + 5 % = 9 % Answer: 9 %