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JEE MainPhysicsGravitation

A body is projected vertically upwards from the surface of a planet. It reaches a maximum height equal to the radius of the planet. The ratio of its projection speed to the escape speed from the surface of the planet is

Options

  1. A1
  2. B1 2
  3. C2
  4. D1 2

Correct answer

D. 1 2

Step-by-step solution

Let M and R be the mass and radius of the planet, respectively. Let v be the projection speed. The initial total mechanical energy of the body at the surface of the planet is E_ i = - GMm R + 1 2 mv^2 At the maximum height h = R , the distance from the center of the planet is r = R + R = 2R . The kinetic energy is zero, so the final total mechanical energy is E_ f = - GMm 2R By conservation of mechanical energy, E_ i = E_ f : - GMm R + 1 2 mv^2 = - GMm 2R 1 2 mv^2 = GMm 2R v = GM R The escape speed from the surface

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