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JEE Main
Exam
JEE Main
Subject
Physics
Chapter
Magnetic Properties of Matter

JEE Main · Physics · Magnetic Properties of Matter

The absolute magnetic permeability of a material is 4π × 10^ -4...

The absolute magnetic permeability of a material is 4π×10−44\pi \times 10^{-4} Wb/A-m. If the permeability of free space is μ0=4π×10−7\mu_0 = 4\pi \times 10^{-7} Wb/A-m, the magnetic susceptibility of the material is:

Options

  1. A999999
  2. B10001000
  3. C10011001
  4. D10−310^{-3}

Correct answer

A. 999999

Step-by-step solution

The relative permeability μr\mu_r of the material is given by the ratio of its absolute permeability to the permeability of free space:

μr=μμ0\mu_r = \dfrac{\mu}{\mu_0}

μr=4π×10−44π×10−7=1000\mu_r = \dfrac{4\pi \times 10^{-4}}{4\pi \times 10^{-7}} = 1000

The relation between relative permeability and magnetic susceptibility χ\chi is:

μr=1+χ\mu_r = 1 + \chi

χ=μr−1\chi = \mu_r - 1

χ=1000−1=999\chi = 1000 - 1 = 999

Answer: 999999
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