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JEE Main
Exam
JEE Main
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Physics
Chapter
Magnetic Properties of Matter

JEE Main · Physics · Magnetic Properties of Matter

A solenoid of length 10 cm and 100 turns is wound over a magnetic...

A solenoid of length 1010 cm and 100100 turns is wound over a magnetic core. The coercivity of the core material is 20002000 A m−1^{-1}. The solenoid has a resistance of 22 Ω\Omega and is connected in series with a battery of emf 2020 V and internal resistance 11 Ω\Omega, along with an unknown external resistor RR. The value of RR required so that the core is just demagnetized is ________ Ω\Omega.

Correct answer

7

Step-by-step solution

To demagnetize the core, the magnetic intensity HH produced by the solenoid must be equal to the coercivity of the core material.

Given:
Coercivity Hc=2000H_c = 2000 A m−1^{-1}
Length of solenoid L=10L = 10 cm =0.1= 0.1 m
Number of turns N=100N = 100

The magnetic intensity is given by H=ni=NLiH = ni = \dfrac{N}{L}i.

Substituting the given values:
2000=1000.1×i2000 = \dfrac{100}{0.1} \times i
2000=1000×i2000 = 1000 \times i
i=2i = 2 A.

The total resistance of the series circuit is Rtotal=R+Rsolenoid+rR_{total} = R + R_{solenoid} + r, where Rsolenoid=2R_{solenoid} = 2 Ω\Omega and r=1r = 1 Ω\Omega.

Using Ohm's law for the complete circuit:
V=i×RtotalV = i \times R_{total}
20=2×(R+2+1)20 = 2 \times (R + 2 + 1)
10=R+310 = R + 3
R=7R = 7 Ω\Omega.

Answer: 77
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