A particle of mass 2 kg is initially moving with a velocity u = 3 i + 4 j ms ⁻¹ . After a time interval of 3 s , its velocity becomes v = 3 i + 4 j + 12 k ms ⁻¹ . If a constant force was acting on the particle during this interval, the magn

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A particle of mass 2 kg is initially moving with a velocity u = 3 i + 4 j ms ⁻¹ . After a time interval of 3 s , its velocity becomes v = 3 i + 4 j + 12 k ms ⁻¹ . If a constant force was acting on the particle during this interval, the magnitude of this force is

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Correct answer: C. 8 N

The initial velocity of the particle is u = 3 i + 4 j ms ⁻¹ . The final velocity after t = 3 s is v = 3 i + 4 j + 12 k ms ⁻¹ . The acceleration of the particle is given by: a = v - u t = 12 k 3 = 4 k ms ⁻² According to Newton's second law, the force acting on the particle is: F = m a = 2 4 k = 8 k N The magnitude of this force is | F | = 8 N . Answer: 8 N

A particle of mass 2 kg is initially moving with a velocity u = 3 i + 4 j ms ⁻¹ . After a time interval of 3 s , its velocity becomes v = 3 i + 4 j + 12 k ms ⁻¹ . If a constant force was acting on the particle during this interval, the magnitude of this force is

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