In a single slit diffraction experiment, the slit width is 0.3 ~mm . The total angular divergence between the third order minima on either side of the central maximum is found to be 1.2 10⁻² ~rad . The wavelength of the light used is ______ nm .

Step-by-step solution

The angular position of the n -th order minimum in single slit diffraction is given by = n a . The total angular divergence between the n -th order minima on either side of the central maximum is 2 = 2n a . Given n = 3 , a = 0.3 10⁻³ ~m , and 2 = 1.2 10⁻² ~rad . Substituting the values: 1.2 10⁻² = 2 3 0.3 10⁻³ = 1.2 10⁻² 0.3 10⁻³ 6 = 0.06 10⁻⁵ ~m = 600 10⁻⁹ ~m = 600 ~nm . Answer: 600