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JEE MainPhysicsMotion in Two Dimensions

Two projectiles A and B are projected from level ground such that they both reach the same maximum height. If the initial speed of projectile A is u and that of projectile B is 3u , the ratio of the sine of their angles of projection with the horizontal, _A : _B , is:

Options

  1. A1:3
  2. B3:1
  3. C1:9
  4. D9:1

Correct answer

B. 3:1

Step-by-step solution

The maximum height reached by a projectile is given by H = v^2 ^2 2g . Since both projectiles reach the same maximum height, their initial vertical velocity components must be equal. Therefore, v_A _A = v_B _B . Substituting the given speeds, we get u _A = 3u _B . Rearranging the terms gives the ratio _A _B = 3 1 . Thus, the required ratio is 3:1 . Answer: 3:1

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