JEE MainPhysicsElectrostatics
Two identical short electric dipoles are placed at the origin. The dipole moment of the first is p ₁ = p i and that of the second is p ₂ = p j . The magnitude of the net electric field and the net electric potential at a point P(d, 0) are respectively:
Options
- A3p 4 ₀ d^3 and p 4 ₀ d^2
- B8 p 4 ₀ d^3 and 2p 4 ₀ d^2
- C5 p 4 ₀ d^3 and p 4 ₀ d^2
- D2 p 4 ₀ d^3 and 0
Correct answer
C. 5 p 4 ₀ d^3 and p 4 ₀ d^2
Step-by-step solution
For the first dipole p ₁ = p i , the point P(d, 0) lies on its axial line. The electric field and potential due to p ₁ at P are: E ₁ = 1 4 ₀ 2p d^3 i V₁ = 1 4 ₀ p d^2 For the second dipole p ₂ = p j , the point P(d, 0) lies on its equatorial line. The electric field and potential due to p ₂ at P are: E ₂ = - 1 4 ₀ p d^3 j V₂ = 0 By the principle of superposition, the net electric field at P is: E _ net = E ₁ + E ₂ = 1 4 ₀ d^3 (2p i - p j ) The magnitude of the net electric field is: | E _ net | = 1 4 ₀ d^3 (2p)^2 +