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JEE MainPhysicsMotion in One Dimension

A small spherical body is dropped from rest into a deep tank of viscous fluid. The fluid exerts a viscous drag force on the body that is directly proportional to its velocity. Which of the following statements correctly describes the graph of the body's acceleration a versus its velocity v ?

Options

  1. AA straight line passing through the origin with a positive slope
  2. BAn exponentially decreasing curve approaching the velocity axis asymptotically
  3. CA parabolic curve passing through the origin and opening downwards
  4. DA straight line with a negative slope, intersecting both the positive acceleration and positive velocity axes

Correct answer

D. A straight line with a negative slope, intersecting both the positive acceleration and positive velocity axes

Step-by-step solution

The equation of motion for a body falling in a viscous fluid is given by ma = mg_ eff - kv , where g_ eff is the effective acceleration due to gravity (accounting for buoyancy) and kv is the viscous drag force. Rearranging this equation for acceleration a , we get: a = g_ eff - ( k m )v This equation is of the form y = c - mx , which represents a straight line with a negative slope ( -k/m ) and a positive y-intercept ( g_ eff ). When v = 0 , a = g_ eff (positive acceleration axis intercept). When a = 0 , v = mg_ ef

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