JEE MainPhysicsElectrostatics
Two solid conducting spheres of radii r₁ and r₂ are placed far apart and connected to each other by a thin conducting wire. If a total charge is given to the system, the ratio of the magnitudes of the electric fields at their surfaces, E₁ : E₂ , is:
Options
- Ar₁ r₂
- Br₁^2 r₂^2
- Cr₂ r₁
- Dr₂^2 r₁^2
Correct answer
C. r₂ r₁
Step-by-step solution
When the two conducting spheres are connected by a wire, charge flows until their surface potentials become equal. Let the common potential be V . The electric field at the surface of a conducting sphere of radius r and potential V is given by E = V r . For the first sphere: E₁ = V r₁ For the second sphere: E₂ = V r₂ Taking the ratio of the electric fields: E₁ E₂ = V r₁ V r₂ = r₂ r₁ Answer: r₂ r₁