JEE MainPhysicsElectrostatics
An infinite non-conducting sheet has a uniform surface charge density + . A solid non-conducting sphere of radius R with a uniform volume charge density + is placed such that its center is at a distance from the sheet. A null point (where the net electric field is zero) exists in the space between the sheet and the sphere, and this point lies outside the sphere. The distance of this null point from the center of the
Options
- AR^3 3
- B2 R^3 3
- C2 R^3 3
- D3 2
Correct answer
C. 2 R^3 3
Step-by-step solution
Let the distance of the null point from the center of the sphere be x . The electric field due to the infinite non-conducting sheet is uniform and its magnitude is given by: E_ sheet = 2 ₀ The electric field due to the solid non-conducting sphere at a point outside it (distance x > R ) is: E_ sphere = 1 4 ₀ Q x^2 where Q = 4 3 R^3 . Substituting Q , we get: E_ sphere = 1 4 ₀ 4 3 R^3 x^2 = R^3 3 ₀ x^2 At the null point, the net electric field is zero, so the magnitudes of the two fields must be equal: E_ sheet = E_