A long solenoid has 1000 turns per meter and carries a current of 3 A . When a certain magnetic material is introduced inside the solenoid to completely fill its core, the magnetic field inside increases by 4 % . The magnetization of the core material is

Step-by-step solution

The percentage increase in the magnetic field is given by _m 100 % , where _m is the magnetic susceptibility of the core material. Given that the percentage increase is 4 % , we have: _m = 4 100 = 0.04 The magnetic intensity H inside the solenoid is determined by the number of turns per unit length n and the current I : H = nI = 1000 3 = 3000 A/m The magnetization M of the core material is related to the magnetic intensity by: M = _m H M = 0.04 3000 = 120 A/m Answer: 120 A/m