A uniform material is subjected to an external pressure of 6 10^6 N m ⁻² , which causes its density to increase by 0.03 % . The bulk modulus of the material is :

Step-by-step solution

For a fixed mass M , the density is = M V . Differentiating both sides, we get = - V V . Thus, a 0.03 % increase in density corresponds to a 0.03 % decrease in volume. Volumetric strain = V V = 0.03 100 = 3 10⁻⁴ The bulk modulus B is given by: B = P ( V V ) B = 6 10^6 3 10⁻⁴ = 2 10¹⁰ N m ⁻² Answer: 2 10¹⁰ N m ⁻²