MHT CET Medical202625 April 2026Evening ShiftBiologyMolecular Basis of InheritanceActual
A 340 Å long segment of DNA molecule has 40 thymine nitrogenous bases, what will be the number of guanine bases in the same segment?
Options
- A10
- B20
- C40
- D60
Correct answer
D. 60
Step-by-step solution
Length of the DNA segment = 340 Distance between two consecutive base pairs in B-DNA = 3.4 Total number of base pairs = 340 3.4 = 100 Total number of nitrogenous bases = 100 2 = 200 According to Chargaff's rule, A = T and G = C . Given number of thymine bases ( T ) = 40 Number of adenine bases ( A ) = 40 Total number of A and T bases = 40 + 40 = 80 Total number of G and C bases = 200 - 80 = 120 Number of guanine bases ( G ) = 120 2 = 60 Answer: 60