A man, homozygous dominant for widows peak (WW), marries a woman with straight hairline homozygous recessive (ww). How many of their off springs will inherit straight hair line?

Step-by-step solution

The genotype of the man is WW (homozygous dominant for widow's peak). The genotype of the woman is ww (homozygous recessive for straight hairline). A cross between the parents ( WW ww ) will produce offspring that all have the genotype Ww (heterozygous). Since the allele for widow's peak ( W ) is dominant over the allele for straight hairline ( w ), all offspring will exhibit the widow's peak phenotype. Therefore, the percentage of offspring inheriting a straight hairline is 0 % . Answer: 0 %