A man, homozygous dominant for widows peak (WW), marries a woman with straight hairline homozygous recessive (ww). How many of their off springs will inherit straight hair line?

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Correct answer: D. 0\ \%

The genotype of the man is WW (homozygous dominant for widow's peak). The genotype of the woman is ww (homozygous recessive for straight hairline). A cross between the parents (WW × ww ) will produce offspring that all have the genotype Ww (heterozygous). Since the allele for widow's peak (W ) is dominant over the allele for straight hairline (w ), all offspring will exhibit the widow's peak phenotype. Therefore, the percentage of offspring inheriting a straight hairline is 0\ \% . Answer: 0\ \%

A man, homozygous dominant for widows peak (WW), marries a woman...

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