What should be the molarity of aqueous solution of K ₂ SO ₄ so that it is isotonic with aqueous 1 M glucose at same temperature, assuming complete dissociation?

Step-by-step solution

For isotonic solutions, the osmotic pressures are equal. ₁ = ₂ i₁ C₁ RT = i₂ C₂ RT For glucose, i₁ = 1 and C₁ = 1 M . For K ₂ SO ₄ , assuming complete dissociation, it yields 2 K ^+ and SO ₄²⁻ , so i₂ = 3 . Let its molarity be C₂ . 1 1 = 3 C₂ C₂ = 1 3 M = 0.333 M Answer: 0.333 M