Calculate the pressure in atm of 48 g oxygen gas in a 2 dm ^3 container at 27 ^ C . [ R = 0.0821 atm dm ^3 K ⁻¹ mol ⁻¹ ]

Step-by-step solution

Given mass of oxygen gas, w = 48 g Molar mass of oxygen gas ( O₂ ), M = 32 g mol ⁻¹ Number of moles, n = w M = 48 32 = 1.5 mol Volume of the container, V = 2 dm ^3 Temperature, T = 27 ^ C = 27 + 273 = 300 K Using the ideal gas equation, PV = nRT P = nRT V P = 1.5 0.0821 300 2 P = 36.945 2 = 18.4725 atm The pressure of the gas is approximately 18.47 atm . Answer: 18.47 atm