A certain organic solvent has H _vap = 28.50 kJ mol ⁻¹ and S _vap = 88.2 J K ⁻¹ mol ⁻¹ at 1 bar. Calculate its normal boiling point (where G = 0 ).

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Correct answer: B. 323.1 K

At the normal boiling point, the liquid and vapour phases are in equilibrium, which gives G = 0 . Using the Gibbs free energy equation: G = H_ vap - T_ b S_ vap = 0 T_ b = H_ vap S_ vap Substituting the given values: T_ b = 28.50 1000 88.2 T_ b = 28500 88.2 = 323.1 K Answer: 323.1 K

A certain organic solvent has H _vap = 28.50 kJ mol ⁻¹ and S _vap = 88.2 J K ⁻¹ mol ⁻¹ at 1 bar. Calculate its normal boiling point (where G = 0 ).

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