What would be the heat released in kJ when 450 cm ^3 of 0.02 M H ₂ SO ₄ is mixed with 650 cm ^3 of 0.1 M NaOH ? (Heat of neutralization of H ₂ SO ₄ and NaOH is -114 kJ/mol of H ₂ SO ₄ )

Step-by-step solution

Number of moles of H ₂ SO ₄ = M V = 0.02 0.450 = 0.009 mol Number of moles of NaOH = M V = 0.1 0.650 = 0.065 mol The neutralization reaction is: H ₂ SO ₄ + 2 NaOH Na ₂ SO ₄ + 2 H ₂ O From the stoichiometry, 0.009 mol of H ₂ SO ₄ requires 0.018 mol of NaOH . Since 0.065 mol of NaOH is available, H ₂ SO ₄ is the limiting reagent. Heat released per mole of H ₂ SO ₄ is 114 kJ . Total heat released = 0.009 114 = 1.026 kJ Answer: 1.026