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MHT CET Medical202624 April 2026Evening ShiftPhysicsAlternating CurrentActual

In an AC circuit, E and I are given by E = 150 (150t) V and I = 150 (150t + 3 ) A. The power dissipated in the circuit is (60)^ = 1/2

Options

  1. A106 W
  2. B150 V
  3. C5625 W
  4. Dzero

Correct answer

C. 5625 W

Step-by-step solution

The given equations are E = 150 (150t) and I = 150 (150t + 3 ) . The peak voltage E₀ = 150 V and the peak current I₀ = 150 A. The phase difference between voltage and current is = 3 = 60^ . The average power dissipated in the circuit is given by P = E_ rms I_ rms . P = E₀ 2 I₀ 2 = E₀ I₀ 2 Substituting the values: P = 150 150 2 (60^ ) P = 22500 2 1 2 = 22500 4 = 5625 W. Answer: 5625 W

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