The energy levels of certain atom are represented in the following figure. During the transition from 2E to E level, a photon of wavelength $\lambda$ is emitted. The wavelength of photon produced during transition from $\dfrac{4E}{3}$ level to E will be

Question

The energy levels of certain atom are represented in the following figure. During the transition from 2E to E level, a photon of wavelength

\lambda

is emitted. The wavelength of photon produced during transition from

\dfrac{4E}{3}

level to E will be
The energy levels of certain atom are represented in the following figure. During the transition from 2E to E level, a

Quantrex Academy · Accepted Answer

Correct answer: A. 3λ

The energy of an emitted photon during a transition is given by

\Delta E = \dfrac{hc}{\lambda}

.

For the transition from

2E

to

E

:

\Delta E_1 = 2E - E = E

\Rightarrow E = \dfrac{hc}{\lambda}

For the transition from

\dfrac{4}{3}E

to

E

, let the wavelength be

\lambda'

:

\Delta E_2 = \dfrac{4}{3}E - E = \dfrac{E}{3}

\Rightarrow \dfrac{E}{3} = \dfrac{hc}{\lambda'}

Substituting

E = \dfrac{hc}{\lambda}

into the above equation:

\dfrac{1}{3} \left( \dfrac{hc}{\lambda} \right) = \dfrac{hc}{\lambda'}

\Rightarrow \lambda' = 3\lambda

Answer:

3\lambda

The energy levels of certain atom are represented in the following...