MHT CET Medical202625 April 2026Morning ShiftPhysicsAtomic PhysicsActual

The ratio of ionization energy of a hydrogen atom in fifth excited state to second excited state is

Options

A1:1
B1:2
C4:1
D1:4

Correct answer

D. 1:4

Step-by-step solution

The ionization energy of a hydrogen atom in the n -th state is given by IE_n = 13.6 n^2 eV. For the fifth excited state, the principal quantum number is n₁ = 6 . For the second excited state, the principal quantum number is n₂ = 3 . The ratio of their ionization energies is: IE₆ IE₃ = 13.6 6^2 13.6 3^2 IE₆ IE₃ = 3^2 6^2 = 9 36 = 1 4 The ratio is 1:4 . Answer: 1:4

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