The equivalent capacitance between 'P' and 'Q' is [A-area of each plate, d-separation between the plates, ₀ -permittivity of free space]

Step-by-step solution

The given arrangement is equivalent to three capacitors connected in parallel between the terminals P and Q, as the potential difference across each section is the same. The capacitance of a parallel plate capacitor with a dielectric is given by C = K ₀ A' d . For the three sections, the area is A' = A 3 and the distance between the plates is d . The individual capacitances are: C₁ = K₁ ₀ (A/3) d = 1 ₀ A 3d = ₀ A 3d C₂ = K₂ ₀ (A/3) d = 2 ₀ A 3d = 2 ₀ A 3d C₃ = K₃ ₀ (A/3) d = 3 ₀ A 3d = 3 ₀ A 3d Since the capacitors