A closely wound solenoid of 1000 turns and area of cross-section 2 × 10^ -4 \ m^2 carries a current of 2 A. It is suspended through its centre and perpendicular to its length, allowing it to turn in a horizontal plane

Question

Quantrex Academy · Accepted Answer

Correct answer: A. 1.7 × 10^ -2 Nm

The magnetic moment of the solenoid is given by

M = NIA

Substituting the given values:

M = 1000 \times 2 \times 2 \times 10^{-4} = 0.4\ \text{A m}^2

The torque acting on the solenoid in a uniform magnetic field is given by

\tau = MB \sin \theta

Substituting the values:

\tau = 0.4 \times 5 \times 10^{-2} \times \sin 60^{}^{\circ}

\tau = 2 \times 10^{-2} \times \dfrac{\sqrt{3}}{2}

\tau = \sqrt{3} \times 10^{-2} \approx 1.732 \times 10^{-2}\ \text{Nm}

Answer:

1.7 \times 10^{-2}

Nm

A closely wound solenoid of 1000 turns and area of cross-section 2...

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