A circular coil having ' n ' turns, each of radius ' r ' carries a current ' I '. The magnetic field at a distance x = 3 \,r from its center, along the axis of the coil, is [μ_0 = permeability of free space ]

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Correct answer: C. (μ_0 nI)/(16r)

The magnetic field at a distance x on the axis of a circular coil of radius r with n turns carrying current I is given by B = μ_0 n I r^2 2(r^2 + x^2)^ 3/2 Given x = 3 r , substituting this value into the formula: B = μ_0 n I r^2 2(r^2 + ( 3 r)^2)^ 3/2 B = μ_0 n I r^2 2(r^2 + 3r^2)^ 3/2 B = μ_0 n I r^2 2(4r^2)^ 3/2 B = (μ_0 n I r^2)/(2(8r^3)) B = (μ_0 n I)/(16r) Answer: (μ_0 nI)/(16r)

A circular coil having ' n ' turns, each of radius ' r ' carries a...

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