A circular loop carrying a current' I' is made of a wire of length 'L'. A uniform magnetic field 'B' exists parallel to the plane of the loop. The torque experienced by the circular loop will be

Step-by-step solution

The length of the wire is L . For a circular loop, the circumference is equal to L . 2 R = L R = L 2 The area of the circular loop is given by: A = R^2 = ( L 2 )^2 = L^2 4 The magnetic dipole moment of the current-carrying loop is: M = IA = IL^2 4 The magnetic field B is parallel to the plane of the loop, which means the angle between the area vector (magnetic moment M ) and the magnetic field B is 90^ . The torque experienced by the loop is: = MB = ( IL^2 4 ) B (90^ ) = IL^2B 4 Answer: IL^2B 4