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MHT CET 202625 AprilEvening Shift
Exam
MHT CET
Year
2026
Date
25 April
Shift
Evening Shift
Subject
Physics
Chapter
Ray Optics

MHT CET 2026 · 25 April · Evening Shift · Physics · Ray Optics

What is the total optical path length of two media in contact with...

What is the total optical path length of two media in contact with thicknesses of dd and d4\dfrac{d}{4} and refractive indices of n1n_1 and n2n_2, respectively?

Options

  1. Ad(n1+4n2)4\dfrac{d(n_1 + 4n_2)}{4}
  2. Bd(4n1+n2)4\dfrac{d(4n_1 + n_2)}{4}
  3. Cd(n1+n2)4\dfrac{d(n_1 + n_2)}{4}
  4. Dd(4n1+n2)d(4n_1 + n_2)

Correct answer

B. d(4n1+n2)4\dfrac{d(4n_1 + n_2)}{4}

Step-by-step solution

Optical path length is given by the product of the refractive index and the geometric thickness of the medium.

For the first medium, the optical path length is x1=n1dx_1 = n_1 d.

For the second medium, the optical path length is x2=n2(d4).<br><br>Thetotalopticalpathlengthisthesumoftheindividualopticalpathlengths:<br><br>x_2 = n_2 \left(\dfrac{d}{4}\right).<br><br>The total optical path length is the sum of the individual optical path lengths:<br><br>x = x_1 + x_2<br><br><br><br>x = n_1 d + n2d4<br><br>\dfrac{n_2 d}{4}<br><br> x = d(4n1+n2)4<br><br>Answer:d(4n1+n2)4\dfrac{d(4n_1 + n_2)}{4}<br><br>Answer: \dfrac{d(4n_1 + n_2)}{4}
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