The angle of minimum deviation produced by a thin prism in air is ₁ . What will be the minimum deviation ( ₂) if the prism is immersed in another liquid medium? _a n_g = 3/2, _a n_l = 4/3

Step-by-step solution

For a thin prism, the angle of minimum deviation is given by = (n - 1)A , where n is the relative refractive index of the prism with respect to the surrounding medium and A is the angle of the prism. When the prism is in air, the deviation is: ₁ = ( _a n_g - 1)A = ( 3 2 - 1 )A = A 2 When the prism is immersed in the liquid, the relative refractive index of the glass with respect to the liquid is: _l n_g = _a n_g _a n_l = 3/2 4/3 = 9 8 The deviation in the liquid is: ₂ = ( _l n_g - 1)A = ( 9 8 - 1 )A = A 8 Taking th