If the temperature of 5 kg mass of a material of a specific heat capacity 200 J/kg ^ ^ C rises from the 30^ ^ C to 40^ ^ C. The heat received is

Correct answer: C. 10000 J Given mass m = 5 kg Specific heat capacity c = 200 J/kg^ ^ C Change in temperature Δ T = 40^ ^ C - 30^ ^ C = 10^ ^ C The heat received is given by the formula Q = mcΔ T Substituting the values, we get Q = 5 × 200 × 10 = 10000 J Answer: 10000 J

MHT CET 202623 AprilEvening Shift

Exam: MHT CET
Year: 2026
Date: 23 April
Shift: Evening Shift
Subject: Physics
Chapter: Thermal Properties of Matter

MHT CET 2026 · 23 April · Evening Shift · Physics · Thermal Properties of Matter

If the temperature of 5 kg mass of a material of a specific heat...

If the temperature of

5

kg mass of a material of a specific heat capacity

200

J/kg ^{}^{\circ}

C rises from the 30^{}^{\circ}

C to

40^{}^{\circ}

C. The heat received is

Options

A $15000$ J
B $12000$ J
C $10000$ J
D $8000$ J

Correct answer

C. $10000$ J

Step-by-step solution

Given mass

m = 5

kg

Specific heat capacity

c = 200

J/kg^{}^{\circ}

C<br><br>Change in temperature

\Delta T = 40^{}^{\circ}

C

- 30^{}^{\circ}

C

= 10^{}^{\circ}

C<br><br>The heat received is given by the formula

Q = mc\Delta T

<br><br>Substituting the values, we get

Q = 5 \times 200 \times 10 = 10000

J<br><br>Answer: 10000

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