Identify the INCORRECT statement for isobaric process.

In an isobaric process, the pressure of the system remains constant, so $\Delta p = 0$.

The work done is given by $W = p\Delta V$. Since the volume changes, $W \neq 0$.

The heat exchanged is $Q = nC_p\Delta T$. Since the temperature changes, $Q \neq 0$.

The change in internal energy is $\Delta U = nC_v\Delta T$. Since the temperature changes, $\Delta U \neq 0$.

The statement $\Delta U = 0$ is true for an isothermal process of an ideal gas, not an isobaric process. Therefore, $\Delta U = 0$ is the incorrect statement.

Answer: $\Delta U = 0$