A gas for which is 3/2 is heated at constant pressure. The percentage of heat supplied for external work is nearly

Step-by-step solution

Heat supplied at constant pressure is given by Q = n C_p T Work done by the gas is given by W = P V = n R T The fraction of heat supplied used for external work is W Q = n R T n C_p T = R C_p Using Mayer's relation C_p - C_v = R and = C_p C_v , we get C_p - C_p = R R C_p = 1 - 1 Given = 3 2 , substituting this value: W Q = 1 - 2 3 = 1 3 Percentage of heat used for external work = 1 3 100 % = 33.33 % This is nearly 33 % . Answer: 33 %