MHT CET Medical202623 April 2026Evening ShiftPhysicsWave OpticsActual
In a diffraction pattern due to a single slit of width a, the first minimum is observed at an angle 30^ when light of wavelength 5000 Å is incident on the slit. The first secondary maximum is observed at an angle of (30)^ = (60)^ = 1 2
Options
- A⁻¹ ( 2 3 )
- B⁻¹ ( 1 2 )
- C⁻¹ ( 3 4 )
- D⁻¹ ( 1 4 )
Correct answer
C. ⁻¹ ( 3 4 )
Step-by-step solution
The condition for the first minimum in a single slit diffraction pattern is given by a = . Substituting = 30^ , we get a 30^ = . Since 30^ = 1 2 , we have a ( 1 2 ) = , which gives a = 2 . The condition for the first secondary maximum is given by a ' = 3 2 . Substituting a = 2 , we get 2 ' = 3 2 . Solving for ' , we get ' = 3 4 . Therefore, ' = ⁻¹ ( 3 4 ) . Answer: ⁻¹ ( 3 4 )