The path difference between the two waves y₁ = a₁ ( t - 2 x + ) and y₂ = a₂ ( t - 2 x + ) is

Step-by-step solution

The given wave equations are: y₁ = a₁ ( t - 2 x + ) y₂ = a₂ ( t - 2 x + ) To compare the phases, we express y₂ in terms of the sine function: y₂ = a₂ ( t - 2 x + + 2 ) The phase of the first wave is ₁ = t - 2 x + The phase of the second wave is ₂ = t - 2 x + + 2 The phase difference between the two waves is: = ₂ - ₁ = ( + 2 ) - = - 2 The relation between path difference x and phase difference is given by: x = 2 Substituting the value of : x = 2 ( - 2 ) Answer: 2 ( - 2 )