MHT CET 202625 AprilMorning Shift
- Exam
- MHT CET
- Year
- 2026
- Date
- 25 April
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Wave Optics
MHT CET 2026 · 25 April · Morning Shift · Physics · Wave Optics
The Brewster's angle θ_B for air-glass interface should be such...
The Brewster's angle for air-glass interface should be such that
(refractive index of glass )
(refractive index of glass )
Options
- A\theta_B = 90^{}^{\circ}
- B45^{}^{\circ} < \theta_B < 90^{}^{\circ}
- C30^{}^{\circ} < \theta_B < 45^{}^{\circ}
- D0^{}^{\circ} < \theta_B < 45^{}^{\circ}
Correct answer
B. 45^{}^{\circ} < \theta_B < 90^{}^{\circ}
Step-by-step solution
According to Brewster's law, the tangent of the polarizing angle (Brewster's angle) is equal to the refractive index of the medium.
Given
We know that \tan 45^{}^{\circ} = 1 and \tan 90^{}^{\circ} \rightarrow \infty.
Since , the angle must lie between 45^{}^{\circ} and 90^{}^{\circ}.
45^{}^{\circ} < \theta_B < 90^{}^{\circ}
Answer: 45^{}^{\circ} < \theta_B < 90^{}^{\circ}
Given
We know that \tan 45^{}^{\circ} = 1 and \tan 90^{}^{\circ} \rightarrow \infty.
Since , the angle must lie between 45^{}^{\circ} and 90^{}^{\circ}.
45^{}^{\circ} < \theta_B < 90^{}^{\circ}
Answer: 45^{}^{\circ} < \theta_B < 90^{}^{\circ}