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MHT CET 202625 AprilEvening Shift
Exam
MHT CET
Year
2026
Date
25 April
Shift
Evening Shift
Subject
Physics
Chapter
Waves and Sound

MHT CET 2026 · 25 April · Evening Shift · Physics · Waves and Sound

For the given wave equation y = 10 π((x)/(4) + (t)/(2)) , the...

For the given wave equation y=10cos⁡π(x4+t2)y = 10\cos\pi\left(\dfrac{x}{4} + \dfrac{t}{2}\right), the CORRECT statement is ( where x is in metre and time t is in second.)

Options

  1. Afrequency =0.25 Hz= 0.25\ \text{Hz}
  2. BWavelength =10 m= 10\ \text{m}
  3. Cvelocity =20 cm/s= 20\ \text{cm/s}
  4. Dangular velocity =2π= 2\pi

Correct answer

A. frequency =0.25 Hz= 0.25\ \text{Hz}

Step-by-step solution

The given wave equation is y=10cos⁡π(x4+t2)y = 10\cos\pi\left(\dfrac{x}{4} + \dfrac{t}{2}\right)

Rewriting the equation, we get y=10cos⁡(π4x+π2t)y = 10\cos\left(\dfrac{\pi}{4}x + \dfrac{\pi}{2}t\right)

Comparing with the standard wave equation y=Acos⁡(kx+ωt)y = A\cos(kx + \omega t), we get:

Angular frequency ω=π2 rad/s\omega = \dfrac{\pi}{2}\ \text{rad/s}

Wave number k=π4 m−1k = \dfrac{\pi}{4}\ \text{m}^{-1}

Frequency f=ω2π=π/22π=0.25 Hzf = \dfrac{\omega}{2\pi} = \dfrac{\pi/2}{2\pi} = 0.25\ \text{Hz}

Wavelength λ=2πk=2ππ/4=8 m\lambda = \dfrac{2\pi}{k} = \dfrac{2\pi}{\pi/4} = 8\ \text{m}

Wave velocity v=fλ=0.25×8=2 m/s=200 cm/sv = f\lambda = 0.25 \times 8 = 2\ \text{m/s} = 200\ \text{cm/s}

Thus, the only correct statement is frequency =0.25 Hz= 0.25\ \text{Hz}.

Answer: frequency =0.25 Hz= 0.25\ \text{Hz}
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