A simple harmonic progressive wave is represented as Y = 0.04 (2t - 0.02x) m. At a given instant of time, the phase difference between two particles 10 m apart is (in radian)

Step-by-step solution

The given equation of the wave is Y = 0.04 ( (2t - 0.02x)) . The phase of the wave at position x and time t is = 2 t - 0.02 x . Comparing this with the standard wave equation Y = A ( t - kx) , the propagation constant is k = 0.02 . At a given instant of time, the phase difference between two particles separated by a distance x is given by = k x . Given the distance between the particles is x = 10 m. Substituting the values, we get = 0.02 (10) = 0.2 = 5 radian. Answer: 5