Consider the following for the two (02) items that follow: Let the...

The given curve is $y = |x - 3|$ and the line is $y = 3$.

To find the points of intersection, we equate the two equations:

$|x - 3| = 3$

$x - 3 = 3$ or $x - 3 = -3$

$x = 6$ or $x = 0$

The points of intersection are $(0,3)$ and $(6,3)$. The vertex of the curve $y = |x - 3|$ is at $(3,0)$.

The area bounded by the curve and the line forms a triangle with vertices $(0,3)$, $(6,3)$, and $(3,0)$.

The length of the base of this triangle (along the line $y = 3$) is $6 - 0 = 6$ units.

The height of the triangle (perpendicular distance from the vertex to the base) is $3 - 0 = 3$ units.

The required area is given by:

Area $= \dfrac{1}{2} \times \text{base} \times \text{height}$

Area $= \dfrac{1}{2} \times 6 \times 3 = 9$ square units.

Answer: $9$ square units