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NDA 2018
Exam
NDA
Year
2018
Subject
Mathematics
Chapter
Continuity and Differentiability

NDA 2018 · Mathematics · Continuity and Differentiability

Consider the function f(x)=\ array l ( 2 x)/(5 x) if x ≠ 0 (2)/(15)...

Consider the function f(x)=\left\{sin⁡2x5x if x≠0215 if x=0\begin{array}{l} \frac{\sin 2 x}{5 x} \text{ if } x \neq 0 \\ \frac{2}{15} \text{ if } x=0 \end{array}\right. Which one of the following is correct in respect of the function?

Options

  1. AIt is not continuous at x=0x=0
  2. BIt is continuous at every x
  3. CIt is not continuous at x=πx=\pi
  4. DIt is continuous at x=0x=0

Correct answer

A. It is not continuous at x=0x=0

Step-by-step solution

lim⁡x→0sin⁡(2x)5x=lim⁡x→0sin⁡(2x)(2)5.(2x)=25\lim _{x \rightarrow 0} \frac{\sin (2 x)}{5 x}=\lim _{x \rightarrow 0} \frac{\sin (2 x)(2)}{5.(2 x)}=\frac{2}{5} But at x=0,f(x)=215x=0, f(x)=\frac{2}{15} Hence, f(x)f(x) is not continuous at x=0x=0.
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