NDA 2015
- Exam
- NDA
- Year
- 2015
- Subject
- Mathematics
- Chapter
- Continuity and Differentiability
NDA 2015 · Mathematics · Continuity and Differentiability
Consider the function f(x)=\ array ccc a x-2 & for & -2 < x < -1 -1...
Consider the function
f(x)=\left\{\right.
What is the value of a for which is continuous at and ?
Options
- A-1
- B1
- C0
- D2
Correct answer
A. -1
Step-by-step solution
f(x)=\left\{\right.$
if $f(x)$ is continuous at $x=-1$
then, \lim _{x \rightarrow-1}(a x-2)=\lim _{x \rightarrow-1}(-1)\begin{aligned}
& \Rightarrow \mathrm{a}(-1)-2=-1 \\
& \Rightarrow \mathrm{a}=-1
\end{aligned}$
if $f(x)$ is continuous at $x=1$
then, $\lim _{x \rightarrow 1}$ a+2(x-1)^2=$\lim _{x \rightarrow 1}$-1\begin{aligned}
& \Rightarrow \mathrm{a}+2(1-1)^2=-1 \\
& \Rightarrow \mathrm{a}=-1
\end{aligned}$$