Let p=(x+y+z) and q=xyz . If vmatrix x & 1 & 1 1 & y & 1 1 & 1 & z vmatrix is positive, then which one of the following is correct ?

Step-by-step solution

Expanding the given determinant along the first row and setting it greater than zero: x(yz - 1) - 1(z - 1) + 1(1 - y) > 0 xyz - x - z + 1 + 1 - y > 0 xyz - (x + y + z) + 2 > 0 Substituting p = x + y + z and q = xyz : q - p + 2 > 0 q + 2 > p Answer: q+2>p