NDA2018MathematicsDifferential EquationsActual
The equation of the curve passing through the point (-1,-2) which satisfies d y d x =-x^2- 1 x^3 is
Options
- A17 x^2 y-6 x^2+3 x^5-2=0
- B6 x^2 y+17 x^2+2 x^5-3=0
- C6 x y-2 x^2+17 x^5+3=0
- D17 x^2 y+6 x y-3 x^5+5=0
Correct answer
B. 6 x^2 y+17 x^2+2 x^5-3=0
Step-by-step solution
aligned & d y d x =-x^2- 1 x^3 & d y= (-x^2- 1 x^3 ) d x & y=- x^3 3 + 1 2 x^2 +c aligned Putting (-1,-2) , we get -2= 1 3 + 1 2 +c C =- 17 6