What is the solution of the differential equation (y d x-x d...

$\frac{y d x-x d y}{y^2}=0$$\begin{aligned} & \therefore \quad y d x-x d y=0 \\ & \therefore \quad \frac{d y}{y}=\frac{d x}{x} \end{aligned}$$$Now integrating both sides,$$\begin{aligned} & \int \frac{d y}{y}=\int \frac{d x}{x} \\ \Rightarrow & \log y=\log x+\log c \\ \Rightarrow & \log y=\log c x \\ \therefore \quad & y=c x \\ \therefore \quad & \text{ Option (B) is correct. } \end{aligned}$$