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NDA 2014
Exam
NDA
Year
2014
Subject
Mathematics
Chapter
Differential Equations

NDA 2014 · Mathematics · Differential Equations

Eliminating the arbitrary constants B and C in the expression y= 2...

Eliminating the arbitrary constants B and C in the expression y=23C(Cx−1)3/2+By=\frac{2}{3 \mathrm{C}}(\mathrm{C} x-1)^{3 / 2}+\mathrm{B}, we get

Options

  1. Ax[1+(dydx)2]=d2ydx2x\left[1+\left(\frac{d y}{d x}\right)^2\right]=\frac{d^2 y}{d x^2}
  2. B2x(dydx)d2ydx2=1+(dydx)22 x\left(\frac{d y}{d x}\right) \frac{d^2 y}{d x^2}=1+\left(\frac{d y}{d x}\right)^2
  3. C(dydx)d2ydx2=1\left(\frac{d y}{d x}\right) \frac{d^2 y}{d x^2}=1
  4. D(dydx)2+1=d2ydx2\left(\frac{d y}{d x}\right)^2+1=\frac{d^2 y}{d x^2}

Correct answer

B. 2x(dydx)d2ydx2=1+(dydx)22 x\left(\frac{d y}{d x}\right) \frac{d^2 y}{d x^2}=1+\left(\frac{d y}{d x}\right)^2

Step-by-step solution

The correct answer is option (B)
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