NDA2014MathematicsDifferential EquationsActual
Paragraph : The general solution of the differential equation (x^2+x+1 ) d y+ (y^2+y+1 ) d x=0 is (x+y+1)=A(1+B x+C y+D x y) where B, C and D are constants and A is parameter. Question : What is D equal to?
Options
- A-1
- B1
- C2
- DNone of the above
Correct answer
C. 2
Step-by-step solution
No Solution Available