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NDA2022MathematicsDifferentiationActual

In y= ^2 ( x^2-x+1 x^2+x+1 ) , then what is d y d x at x=0 equal to?

Options

  1. A-2
  2. B0
  3. C1
  4. D2

Correct answer

B. 0

Step-by-step solution

aligned y= & [ ( x^2-x+1 x^2+x+1 ) ]^2 d y d x = & 2 ( x^2-x+1 x^2+x+1 ) x^2+x+1 x^2-x+1 & (2 x-1) (x^2+x+1 )-(2 x+1) (x^2-x+1 ) (x^2+x-1 )^2 aligned aligned & Put x=0 & d y d x =0 aligned

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