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NDA2015MathematicsDifferentiationActual

Consider the parametric equation x= a (1-t^2 ) 1+t^2 , y= 2 a t 1+t^2 What is d y d x equal to?

Options

  1. Ay x
  2. B- y x
  3. Cx y
  4. D- x y

Correct answer

D. - x y

Step-by-step solution

Here, x^2+y^2=a^2 2 x+2 y d y d x =0 d y d x = 2 x -2 y =- x y Option (D) is correct.

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